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  4. Three charges Q,(.+q.) and (.+q.) are placed at the vertices of an equilateral triangle of side 1m as shown in the figure. If the net electrostatic energy of the system is zero, then Q is equal to: <img class=img-fluid question-image alt=Question src=https://cdn.tardigrade.in/q/nta/p-8whyz7cg5fb7ljny.jpg />

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Q. Three charges $Q,\left(\right.+q\left.\right)$ and $\left(\right.+q\left.\right)$ are placed at the vertices of an equilateral triangle of side $1m$ as shown in the figure. If the net electrostatic energy of the system is zero, then $Q$ is equal to:
Question

NTA AbhyasNTA Abhyas 2020

Solution:

$U=\frac{k q Q}{l}+\frac{k q Q}{l}+\frac{k q^{2}}{l}=0$
$Q=-\frac{q}{2}$