Q.
Three charges $ {{Q}_{0}},-q $ and $ -q $ are placed at the vertices of an isosceles right angle triangle as in the figure. The net electrostatic potential energy is zero if $ {{Q}_{0}} $ is equal to
Solution:
Here total electrostatic potential energy is zero ie,
$ \frac{-{{Q}_{0}}q}{l}-\frac{q{{Q}_{0}}}{l}+\frac{{{q}^{2}}}{\sqrt{2}l}=0 $
On solving, $ {{Q}_{0}}=\frac{q}{2\sqrt{2}}=\frac{2q}{\sqrt{32}} $
