Q. Three charges $2q,-q,-q$ are located at the vertices of an equilateral triangle. At the circumcentre of the triangle
Solution:
Potential due to charge -q at A
$ {{V}_{A}}=\frac{1}{4\pi {{\varepsilon }_{0}}K}\frac{-q}{{{({{r}^{2}})}^{1/2}}} $
Potential due to charge -q at B
$ {{V}_{B}}=\frac{1}{4\pi {{\varepsilon }_{0}}K}\frac{-q}{{{({{r}^{2}})}^{1/2}}} $
Potential due to charge
$ +2q $ at C $ {{V}_{C}}=\frac{1}{4\pi {{\varepsilon }_{0}}K}\frac{2q}{{{({{r}^{2}})}^{1/2}}} $
Total potential at centre
$ V={{V}_{A}}+{{V}_{B}}+{{V}_{C}} $
$ V=0 $
From charge configuration at the centre electric field is non-zero.
