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  4. Three charged capacitors, C1 =17 μ F , C 2=34 μ F , C 3=41 μ F and two open switches, S1 and S 2 are assembled into a network with initial voltages and polarities, as shown. Final status of the network is attained when the two switches, S 1 and S 2 are closed. In the figure, the final charge on capacitor C 3 in mC, is closet to: <img class=img-fluid question-image alt=image src=https://cdn.tardigrade.in/img/question/physics/e09e993225b4c22dad3dbeb468cc879b-.png />

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Q. Three charged capacitors, $C_{1} =17 \mu F , C _{2}=34 \mu F , C _{3}=41 \mu F$ and two open switches, $S_{1}$ and $S _{2}$ are assembled into a network with initial voltages and polarities, as shown. Final status of the network is attained when the two switches, $S _{1}$ and $S _{2}$ are closed. In the figure, the final charge on capacitor $C _{3}$ in $mC$, is closet to:
image

Electrostatic Potential and Capacitance

Solution:

Circuit is short when both switch $S _{1}$ & $S _{2}$ is closed
So $V_{c_{3}}=0$
$q=0$