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  4. Three capacitors of capacitances 3 μ F,9 μ F and 18 μ F are connected once in series and another time in parallels. The ratio of equivalent capacitances in the two cases (Cs/Cp) will be

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Q. Three capacitors of capacitances $3\,\mu F$,$9\,\mu F$ and $18\,\mu F$ are connected once in series and another time in parallels. The ratio of equivalent capacitances in the two cases $(C_s/C_p)$ will be

Electrostatic Potential and Capacitance

Solution:

$\frac{1}{C_s} = \frac{1}{3} + \frac{1}{9} + \frac{1}{18} = \frac{1}{2}$ . Hence $C_s = 2 \, \mu F$
$C_p = 3 + 9 + 18 = 30 \, \mu F$
Therefore $C_s /C_p $ = 2/30 = 1 /15.