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  4. Three capacitors of capacitances 2 μ F , 5 μ F , 8 μ F are connected first in parallel combination and then in series combination, The ratio of their equivalent capacitances will be

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Q. Three capacitors of capacitances $2 \mu F$ , $5 \mu F $, $8 \mu F$ are connected first in parallel combination and then in series combination, The ratio of their equivalent capacitances will be

Electrostatic Potential and Capacitance

Solution:

$C _{ P }=2+5+8=15\, \mu F$
$\frac{1}{ C _{ s }}=\frac{1}{2}+\frac{1}{5}+\frac{1}{8}=\frac{20+8+5}{40}$
$C _{ s }=\frac{40}{33}$
$\frac{ C _{ P }}{ C _{ S }}=\frac{15}{40} \times 33$
$ \approx \frac{12}{1}$