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Physics
Three capacitors each of capacity 4 μ F are to be connected in such a way that the effective capacitance is 6 μ F. This can be done by
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Q. Three capacitors each of capacity $4\, \mu F$ are to be connected in such a way that the effective capacitance is $6\, \mu F$. This can be done by
A
Connecting them in parallel
6%
B
Connecting two in series and one in parallel
73%
C
Connecting two in parallel and one in series
15%
D
Connecting all of them in series
6%
Solution:
The given circuit can be drawn as follows
$\Rightarrow C_{A B}=2+4=6\, \mu F$