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Physics
Three capacitors each of capacitance C and breakdown voltage V are joined in series. The capacitance and breakdown voltage of the combination is
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Q. Three capacitors each of capacitance C and breakdown voltage V are joined in series. The capacitance and breakdown voltage of the combination is
A
$3C, 3V$
B
$\frac {C}{3} , 3V$
C
$3C , \frac {V}{3}$
D
$\frac{C}{3} , \frac {V}{3}$
Solution:
In series $C_{eff} = C/3.$
Effective potential = $V + V + V = 3V$