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Q. Three capacitors $A, B$, and $C$ are connected in a circuit as shown in figure. What is the charge in $\mu C$ on the capacitor $B$ ?Physics Question Image

Electrostatic Potential and Capacitance

Solution:

Capacitors $B$ and $C$ are in parallel, then $A$ is in series.
$C_{ eq }=\frac{2 \times(3+4)}{2+(3+4)}=\frac{14}{9} \mu F$
$Q=C_{ eq } V=\frac{14}{9}(7-6)=\frac{14}{9} \mu C$
$Q$ will be divided between $B$ and $C$. So charge on $B$ is
$q=\frac{3 \times(14 / 9)}{3+4}=\frac{2}{3} \mu C$