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Q. Three bricks each of length $L$ and mass $M$ are arranged as shown from the wall. The distance of the centre of mass of the system from the wall isPhysics Question Image

KEAMKEAM 2010System of Particles and Rotational Motion

Solution:

$ {{x}_{1}}=\frac{L}{2} $
$ {{x}_{2}}=L $
$ {{x}_{3}}=L+\frac{L}{4} $
$ {{x}_{3}}=\frac{5L}{4} $
$ \therefore $ $ {{x}_{CM}}=\frac{{{m}_{1}}{{x}_{1}}+{{m}_{2}}{{x}_{2}}+{{m}_{2}}{{x}_{3}}}{3m} $
$ =\frac{\frac{mL}{2}+mL+\frac{m5L}{4}}{3m} $
$ =\frac{11L}{12} $

Solution Image