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  4. Three blocks of masses m , 3 m and 5 m are connected by massless strings and pulled by a force F on a frictionless surface as shown in the figure below. The tension P in the first string is 16 N If the point of application of F is changed as given below The value of P and Q shall be

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Q. Three blocks of masses $m , 3\, m$ and $5\, m$ are connected by massless strings and pulled by a force $F$ on a frictionless surface as shown in the figure below. The tension $P$ in the first string is $16\, N$ If the point of application of $F$ is changed as given below
The value of $P$ and $Q$ shall bePhysics Question Image

AMUAMU 2011Laws of Motion

Solution:

Let a be the common acceleration of the system
$ \therefore a=\frac{F}{m+3 m+5 m}=\frac{F}{9 m} \ldots .$ (i)
$\therefore P=(3 m+5 m) a$
$16=8 \,m a(\because P=16 N(\text { Given })] $
$a=\frac{2}{m}$
Substituting this value of a in eqn(i), we get $F=18\, N$

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