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Q. Three blocks of masses $m_1, m_2$ and $m_3$ kg are placed in contact with each other on a frictionless table. A force $F$ is applied on the heaviest mass $m_1$; the acceleration of $m_3$ will bePhysics Question Image

BHUBHU 2008Laws of Motion

Solution:

The acceleration of mass $m_{3}$
$=$common acceleration of the system
$=\frac{\text { force applied }}{\text { total mass }} $
$=\frac{F}{m_{1}+m_{2}+m_{3}}$