Question

Three blocks are connected as shown in figure on a horizontal frictionless table. If $m_{1} = 1 \,kg, m_{2}=8\,kg, m_{3} = 27 \,kg$ and $T_{3} = 36 \,N$, $T_{2}$ will be

• A. $18\, N$
• B. $9 \,N$
• C. $3.375 \,N$
• D. $1.75 \,N$

Answer 1

Answer: (B)

$T_{3}=(m_{1}m_{2}+m_{3})a$
$\Rightarrow 36=(1+8+27)a$
$\Rightarrow a=1\,m/s^{2}$
Now $T_{2} = (m_{1}+m_{2})a$
$=(1+8)\times 1=9\,N$