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Q.
Three $2\, \Omega$ resistors are connected to form a triangle. The resistance between any two corners is
ManipalManipal 2017
Solution:
In triangle formation, two resistors are in series and their sum is connected in parallel.
Therefore,
$R'=2\, \Omega+2\, \Omega=4\, \Omega$
$\frac{1}{R}''=\frac{1}{4}+\frac{1}{2}=\frac{3}{4} \Omega$
$R''=\frac{4}{3} \Omega$