Q.
This circuit acts as OR gate.
Reason Truth table for two input OR gate is
$A$
$B$
$Y$
0
0
0
0
1
1
1
0
1
1
1
1
| $A$ | $B$ | $Y$ |
|---|---|---|
| 0 | 0 | 0 |
| 0 | 1 | 1 |
| 1 | 0 | 1 |
| 1 | 1 | 1 |
Semiconductor Electronics: Materials Devices and Simple Circuits
Solution:
Truth table for given circuit is
$A$
$B$
$X=\overline{A+B}$
$Y =\overline{ X }$
0
0
1
0
0
1
0
1
1
0
0
1
1
1
0
1
Hence, the given circuit acts as OR gate.
| $A$ | $B$ | $X=\overline{A+B}$ | $Y =\overline{ X }$ |
|---|---|---|---|
| 0 | 0 | 1 | 0 |
| 0 | 1 | 0 | 1 |
| 1 | 0 | 0 | 1 |
| 1 | 1 | 0 | 1 |