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  4. They decay constant of radium is 4.28 × 10-4 per year. Its half life will be

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Q. They decay constant of radium is $4.28 \times 10^{-4}$ per year. Its half life will be

Nuclei

Solution:

$T =\frac{0.6931 \times 1}{\lambda}=\frac{0.6931}{4.28 \times 10^{-4}}$ year $=1620$ years