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  4. There is a current of 4.8 ampere in a conductor. The number of electrons per second that cross any section normal to the direction of flow is

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Q. There is a current of 4.8 ampere in a conductor. The number of electrons per second that cross any section normal to the direction of flow is

Current Electricity

Solution:

Let $N$ electrons are flowing through a conductor in time $t$.
$\therefore $ Current $, I=\frac{N e}{t}$
or $\frac{N}{t}=\frac{I}{e}=\frac{4.8}{1.6 \times 10^{-19}}=3 \times 10^{19}$ electrons per second