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Q.
There are two isotopes of an element with atomic mass z. Heavier one has atomic mass z + 2 and lighter one has z - 1, then abundance of lighter one is
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Solution:
Let the per cent abundance of lighter isotope is $ \therefore $ Atomic mass, $ z=\frac{x(z-1)+(100-x)\,(z+2)}{x+100-x} $ $ 3x=200 $ or $ x=66.6% $