Q. There are two common oxides of sulphur, one of which contains $50\% O_2$ by weight, the other almost exactly $60\%$. The weights of sulphur which combine with $1\,g$ of $O_2$ (fixed) are in the ratio of
Some Basic Concepts of Chemistry
Solution:
First oxide
Second oxide
Sulphur 50%
40%
Oxygen 5Q%
40%
In first oxide 1 parts oxygen combines with sulphur $=\frac{50}{50}=1$
Similarly for second oxide $=\frac{40}{60}=0.67$
So the ratio is $1 : 0.67$ or $3 : 2$
| First oxide | Second oxide |
| Sulphur 50% | 40% |
| Oxygen 5Q% | 40% |