Q.
There are four complexes of Ni. Select the complexes/es which will be attracted by magnetic field:
(I) $\left(\left[N i \left(C N\right)_{4}\right]\right)^{2 -}$ (II) $\left[N i C l_{4}\right]^{2 -}$ (III) $\left[N i \left(C O\right)_{4}\right]$ (IV) $\left(\left[N i \left(N H_{3}\right)_{6}\right]\right)^{2 +}$
NTA AbhyasNTA Abhyas 2020Coordination Compounds
Solution:
Only $\left[N i C l_{4}\right]^{2 -}$ and $\left(\left[N i \left(N H_{3}\right)_{6}\right]\right)^{2 +}$ are paramagnetic so will be attracted in magnetic field.
Complex O.S HBZ Geometry Unpaired Magnetic property $\left[N i C l_{4}\right]^{2 -}$ +2 $sp^{3}$ Tetrahadral 2 Paramagnetic $\left(\left[N i \left(C N\right)_{4}\right]\right)^{2 -}$ +2 $dsp^{2}$ Square planar 0 Diamagnetic $\left[N i \left(C O\right)_{4}\right]$ 0 $sp^{3}$ Tetrahadral 0 Diamagnetic $\left(\left[N i \left(N H_{3}\right)_{6}\right]\right)^{2 +}$ +2 $sp^{3}d^{2}$ Octahedral 2 Paramagnetic
| Complex | O.S | HBZ | Geometry | Unpaired | Magnetic property |
| $\left[N i C l_{4}\right]^{2 -}$ | +2 | $sp^{3}$ | Tetrahadral | 2 | Paramagnetic |
| $\left(\left[N i \left(C N\right)_{4}\right]\right)^{2 -}$ | +2 | $dsp^{2}$ | Square planar | 0 | Diamagnetic |
| $\left[N i \left(C O\right)_{4}\right]$ | 0 | $sp^{3}$ | Tetrahadral | 0 | Diamagnetic |
| $\left(\left[N i \left(N H_{3}\right)_{6}\right]\right)^{2 +}$ | +2 | $sp^{3}d^{2}$ | Octahedral | 2 | Paramagnetic |