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Q. There are four boxes $B_1, B_2, B_3$ and $B_4$. Box $B_1$ has $i$ cards and on each card a number is printed, the numbers are from 1 to i.A box is selected randomly, the probability of selecting box $B_i$ is $\frac{i}{10}$ and a card is drawn. Let $E _{ i }$ represent the event that a card with number ' $i$ ' is drawn.
$P \left( E _1\right)$ is equal to

Probability - Part 2

Solution:

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$P \left( B _1\right)=\frac{1}{10} ; P \left( B _2\right)=\frac{2}{10} ; P \left( B _3\right)=\frac{3}{10} ; P \left( B _4\right)=\frac{4}{10} $
$P \left( E _1\right)=\frac{1}{10} \times(1)+\left(\frac{2}{10} \times \frac{1}{2}\right)+\left(\frac{3}{10} \times \frac{1}{3}\right)+\left(\frac{4}{10} \times \frac{1}{4}\right)=\frac{4}{10}=\frac{2}{5}$