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Q. There are 9 children comprising of 3 bos and 6 girls. Let $m$ denotes the number of ways when the 3 boys are in succession and $n$ denotes the corresponding figure when the two end position are occupied by boys. If $m = kn$ then $k$ is equal to

Permutations and Combinations

Solution:

$m =3 ! \cdot 7 ! \,\,\,B _{1} B _{2} B _{3} \,\,\,G _{1} G _{2} \ldots G _{6}$
$m ={ }^{3} C _{2} 2 ! 7 !=3 ! 7 !$. Hence $k =1$