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Q. The $ Z $ isomer among the following is

AMUAMU 2011Hydrocarbons

Solution:

image
Out of two groups, i.e. $—Cl$ and $—CH_3$ attached to the $C-1$ atom , the atomic number of $Cl$ is greater than the $C$-atom of $—CH_3$ group. Hence, here $Cl$ is given priority over $—CH_3$ group. Similarly, out of two groups attached to the $C-2$ atom i.e., $—Br$ and $—CH_2CH_3$ the atomic number of $Br$ is greater than the $C$ atom of $—CH_2CH_3$ group. Thus, $Br$ gets priority over $C$ atom of $—CH_2CH_3$ group. Hence, the compound looks like:
image
It is very clear that the bulky groups are at the same side of the double bond, hence this is a $Z$-isomer.