1. Tardigrade
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  3. Chemistry
  4. The yield of the products in the reaction, A2(g)+2B(g) rightharpoons C(g)+Q. kJ would be higher at

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Q. The yield of the products in the reaction, $A_{2(g)}+2B_{(g)} \leftrightharpoons C_{(g)}+Q. kJ$ would be higher at

KCETKCET 2013Equilibrium

Solution:

$A_{2}(g)+2 B(g) \rightleftharpoons C(g)+Q \,kJ$

Obviously, the forward reaction is exothermic. Thus, according to Le-Chatelier's principle, the lower is temperature, greater would be the yield of ammonia. Also, the forward reaction occurs with decrease in number of gaseous molecules. Thus, according to Le-Chatelier's principle an increase in pressure, will shift the equilibrium in a direction in which the number of gaseous molecules decreases. In other words high pressure will favour the formation of products.