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  4. The % yield of ammonia as a function of time in the reaction N2(g)+ 3H2(g) leftharpoons 2NH3(g), Δ H < 0 at (P, T1) is given below. <img class=img-fluid question-image alt=image src=https://cdn.tardigrade.in/img/question/chemistry/05c7754c33c26c59ea9179d2955e33c3-.jpeg /> If this reaction is conducted at (P, T2), with T2 > T1, the % yield of ammonia as a function of time is represented by

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Q. The $\%$ yield of ammonia as a function of time in the reaction $N_{2(g)}+ 3H_{2(g)} \rightleftharpoons 2NH_{3(g)}$, $\Delta H < 0$ at $(P, T_1)$ is given below.
image
If this reaction is conducted at $(P, T_2)$, with $T_2 > T_1$, the $\%$ yield of ammonia as a function of time is represented by

Equilibrium

Solution:

$N_{2(g)} +3H_{(g)}\xrightleftharpoons[endo]{exo} 2NH3_{(g)}$; $\Delta H < 0$
Initially, with increase in temperature $(T_2 > T_1) \,\%$ yield increases.
Afterwards, equilibrium is reached and if the temperature is increased, i.e., heat is supplied to the system, then according to Le Chatelier's principle, the equilibrium will shift in the backward direction, where the heat is absorbed. Hence, the $\%$ yield decreases.