Given mid-points of a triangle are $(0,1),(1,1)$ and $(1,0)$. Plotting these points on a graph paper and make a triangle.
So, the sides of a triangle will be $2,2$ and $\sqrt{2^{2}+2^{2}}$ i.e. $2 \sqrt{2}$
$x $ -coordinate of incentre $=\frac{2 \times 0+2 \sqrt{2} \cdot 0+2 \cdot 2}{2+2+2 \sqrt{2}}$
$=\frac{2}{2+\sqrt{2}} \times \frac{2-\sqrt{2}}{2-\sqrt{2}}=2-\sqrt{2} $