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Q. The work function of a metal is $4.2\, eV$, its threshold wavelength will be:

Dual Nature of Radiation and Matter

Solution:

$W_{0}=\frac{6.6 \times 10^{-34} \times 3 \times 10^{8}}{1.6 \times 10^{-19} \times \lambda_{0}}$
$=\frac{12375}{\lambda_{0}}$
$=\frac{12375}{4.2}=2945 \mathring{A}$