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Chemistry
The work done on the system when one mole of an ideal gas at 500 K is compressed isothermally and reversibly to 1 / 10 th of its original volume ( R =2 cal ) -
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Q. The work done on the system when one mole of an ideal gas at $500\, K$ is compressed isothermally and reversibly to $1 / 10$ th of its original volume $( R =2$ cal $)$ -
Thermodynamics
A
500 kCal
18%
B
1.51 kCal
25%
C
-23.03 kCal
12%
D
2.303 kCal
45%
Solution:
$w=-2.303 \,R T\, \log \frac{v_{2}}{v_{1}}$
$=-2.303 \times 2 \times 500 \log \frac{1}{10}$
$=-2.303 \times 10^{3} \log 10^{-1}$
$=2.303\, kCal$