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Q. The work done on the system when one mole of an ideal gas at $500\, K$ is compressed isothermally and reversibly to $1 / 10$ th of its original volume $( R =2$ cal $)$ -

Thermodynamics

Solution:

$w=-2.303 \,R T\, \log \frac{v_{2}}{v_{1}}$

$=-2.303 \times 2 \times 500 \log \frac{1}{10}$

$=-2.303 \times 10^{3} \log 10^{-1}$

$=2.303\, kCal$