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  4. The work done in an adiabatic change in a particular gas depends only upon

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Q. The work done in an adiabatic change in a particular gas depends only upon

Thermodynamics

Solution:

In adiabatic process, no heat is taken or given by the system
i.e., $\Delta Q =0 \Rightarrow \Delta U =-\Delta W$
If $\Delta W$ is negative (work done on system), then $\Delta U$ increases $\&$ temperature increases and vice-versa. So work done in adiabatic change in particular gas (ideal gas) depends on change in temperature.