1. Tardigrade
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  3. Chemistry
  4. The work done by the gas liberated when 50 g of iron (molar mass 55.85 g mol -1 ) reacts with hydrochloric acid in an open beaker at 25° C

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Q. The work done by the gas liberated when $50\, g$ of iron (molar mass $55.85\, g\, mol ^{-1}$ ) reacts with hydrochloric acid in an open beaker at $25^{\circ} C$

AMUAMU 2012

Solution:

$\underset{55.85\,g}{Fe (s)}+2 HCl ( aq ) \rightarrow FeCl _{2}( aq )+\underset{1 mol }{ H _{2}}( g )$
$n=\frac{50}{55.85}=0.895\, mol$
$W=-n R T-0.895 \times 8.314 \times 10^{-3} \times 298$
$=-2217.42 \times 10^{-3}=-2.2\, kJ$