1. Tardigrade
  2. Question
  3. Chemistry
  4. The weight of 350 mL of a diatomic gas at 0° C and 2 atm pressures is 1 g. The weight of one atom in gram is: (N = Avogadro's number)

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Q. The weight of $350\, mL$ of a diatomic gas at $0^{\circ} C$ and $2 \,atm $ pressures is $1 \,g$. The weight of one atom in gram is: (N = Avogadro's number)

States of Matter

Solution:

$PV = nRT$

Let the atomic weight be A

$2 \times \frac{350}{1000}=\frac{1}{2 A } \times 0.0821 \times 273$

$A=\frac{224}{14}=16$

Mass of one atom $=\frac{16}{ N _{ A }} g$