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  4. The weight of 1 × 1022 molecules of CuSO4.5H2O is

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Q. The weight of $1 \times 10^{22}$ molecules of $CuSO_4.5H_2O$ is

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Solution:

$\left[\because Molecular weight of CuSO_{4}.5H_{2}O=63.5+32+64+90=249.5\right]$
$6\times10^{22}$ molecules has weight $ = \,249 \,g$
$1 \times 10^{22}$ molecules has weight$=\frac{249.5\times1\times10^{22}}{6\times10^{23}}$
$\, =\, 4.158$