Question

The wavelength of maximum energy, released during an atomic explosion was $2.93 \times 10^{-10} m$. Given that the Wien's constant is $2.93 \times 10^{-3} m - K$, the maximum temperature attained must be of the order of :

• A. $10^{-7}K$
• B. $10^{7}K$
• C. $10^{-3}K$
• D. $5.86\, \times 10^{7}K$

Answer 1

Answer: (B)

Wien's displacement law is given by
$\lambda_{m} T=$ constant (say b).
Given, $b =$ Wien's constant
$=2.93 \times 10^{-3} m - K$
$\lambda_{m} =2.93 \times 10^{-10} m$
Substituting the values, we obtain
$T =\frac{b}{\lambda_{m}}$
$=\frac{2.93 \times 10^{-3}}{2.93 \times 10^{-10}}$
$=10^{7} K$