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Q. The wavelength of light in two liquids '$x$' and '$y$' is $3500\,\mathring{A}$ and $7000 \,\mathring{A}$, then the critical angle will be

Solution:

$\sin \theta_{ c }=\frac{1}{ R \mu_{ D }} ; \,\,\,\left[\because \,\,\mu \propto \frac{1}{\lambda}\right]$
$\sin \theta_{ C }=\frac{\lambda_{ D }}{\lambda_{ R }}=\frac{3500}{7000}\,\mathring{A}$
$; \sin \theta_{ C }=\frac{1}{2} ; \theta_{ C }=30^{\circ}$