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  4. The wavelength of light in the visible region is about 760 nm for red colour. The energy of photon in eV at the red end of the visible spectrum is

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Q. The wavelength of light in the visible region is about $760\, nm$ for red colour. The energy of photon in $eV$ at the red end of the visible spectrum is

Dual Nature of Radiation and Matter

Solution:

For red light, $\lambda=760 nm$
Energy, $E=h v=\frac{h c}{\lambda}$
Hence $ E=\frac{6.63 \times 10^{-34} \times 3 \times 10^{8}}{760 \times 10^{-9}}$
$=2.62 \times 10^{-19} J$
$=\frac{2.62 \times 10^{-19}}{1.6 \times 10^{-19}} \,eV =1.64\, eV$