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Q. The wavelength of light in the visible region is about $390 \,nm$ for violet colour and about $760\, nm$ for red colour. The energy of photon in $eV$ at violet end is, the energy of photon in $eV $ at the red end of the visible spectrum is

Dual Nature of Radiation and Matter

Solution:

For red light, $\lambda=760\,nm$
$E=\frac{6.63\times10^{-34}\times3\times10^{8}}{760\times10^{-9}}J$
$=2.62\times10^{-19}J =\frac{2.62\times10^{-19}}{1.6\times10^{-19}}eV$
$=1.64\,eV$