1. Tardigrade
  2. Question
  3. Physics
  4. The wavelength of light emitted due to transition of electron from second orbit to first orbit in hydrogen atom is

Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. The wavelength of light emitted due to transition of electron from second orbit to first orbit in hydrogen atom is

Rajasthan PMTRajasthan PMT 2003Atoms

Solution:

From Bohr's theory, wavelength of radiations emitted in $H$-atom
$\frac{1}{\lambda}=R\left(\frac{1}{n_{2}^{2}}-\frac{1}{n_{1}^{2}}\right)$
Here $n_{1}=2, n_{2}=1, R=1.097 \times 10^{7} m ^{-1}$
$\therefore \frac{1}{\lambda} =R\left(\frac{1}{1^{2}}-\frac{1}{2^{2}}\right)=\frac{3}{4} R $
$\Rightarrow \lambda=\frac{4}{3 R} =\frac{4}{3 \times 1.097 \times 10^{7}} $
$=1.215 \times 10^{-7} m $
$=1215 \,\mathring{A}$