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  4. The wavelength of first line of Balmer spectrum of hydrogen will be :

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Q. The wavelength of first line of Balmer spectrum of hydrogen will be :

Structure of Atom

Solution:

$\frac{1}{\lambda}= R _{ H }\left[\frac{1}{2^{2}}-\frac{1}{ n ^{2}}\right]$

for first line $n=3$,

$\therefore \frac{1}{\lambda}=109678\left[\frac{1}{2^{2}}-\frac{1}{3^{2}}\right]$

$\lambda=6569\, \mathring{A}$