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Q. The wavelength difference of light waves of wave numbers $ 2\times {{10}^{6}}\,/m $ and $ 2.25\times {{10}^{6}}/m $ is

VMMC MedicalVMMC Medical 2011

Solution:

$ \lambda =\frac{1}{2\times {{10}^{6}}}-\frac{1}{2.25\times {{10}^{6}}} $ $ =\frac{2.25-2}{2\times 2.25\times {{10}^{6}}} $ $ =\frac{0.25}{2\times 2.25\times {{10}^{6}}} $ $ =0.0556\times {{10}^{-6}}m $