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Q. The volume $(V)$ of a monatomic gas varies with its temperature $(T)$, as shown in the graph. The ratio of work done by the gas, to the heat absorbed by it, when it undergoes a change from state $A$ to state $B$, isPhysics Question Image

NEETNEET 2018Thermodynamics

Solution:

Given process is isobaric
$dQ = n \,C_{p}\, dT$
$ dQ = n\,\left(\frac{5}{2} R\right)\,dT $
$dW = P \,dV = n \,RdT $
Required ratio $= \frac{dW}{dQ} = \frac{nRdT}{n\left(\frac{5}{2}R\right)dT} = \frac{2}{5} $