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  4. The volume of neon gas in cm3 at STP having the same number of atoms as that present in 800 mg of Ca is (At. mass: Ca = 40 g mol-1, Ne = 20 g mol-1)

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Q. The volume of neon gas in $cm^3$ at $STP$ having the same number of atoms as that present in $800\, mg$ of $Ca$ is (At. mass: $Ca = 40 \,g \,mol^{-1}, Ne = 20 \, g \,mol^{-1})$

KEAMKEAM 2013Some Basic Concepts of Chemistry

Solution:

Mass of $Ca =800\, mg =\frac{800}{1000}=0.8 \,g$

Moles of $Ca$ in $0.8 \,g=\frac{0.8}{40}=2 \times 10^{-2}$

$\because$ At STP, volume of 1 mole $=22400\,cm ^{3}$

$\therefore $ At STP, volume of $2 \times 10^{-2}$ moles

$=22400 \times 2 \times 10^{-2}=448\, cm ^{3}$