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  4. The volume of H2 obtained at S.T.P. when Mg obtained by passing a current of 0.5 amp through molten MgCl2 for 32.2 minutes is treated with excess dilute HCl is approximately [Eq. mass of Mg = 12)

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Q. The volume of $H_2$ obtained at S.T.P. when $Mg$ obtained by passing a current of $0.5$ amp through molten $MgCl_2$ for $32.2$ minutes is treated with excess dilute $HCl$ is approximately [Eq. mass of $Mg = 12$)

COMEDKCOMEDK 2012Electrochemistry

Solution:

Mass of Mg deposited = Zlt
$ = \frac{12}{96500} \times 0.5 \times 32.2 \times 60$
= $ 0.12012 \, g$
Now,
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