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  4. The volume of H2 gas at NTP obtained by passing 4 amperes through acidified H2O for 30 minutes is

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Q. The volume of $H_2$ gas at NTP obtained by passing $4$ amperes through acidified $H_2O$ for $30$ minutes is

Electrochemistry

Solution:

Quantity of electricity passed
$= 4 \,A \times (30 \times 60s) = 7200 \,C$
$2H_2O + 2e^-\rightarrow H_2 + 2OH^-$
$2 \times 96500 \,C$ liberate $ H_2 = 22.4L$ at $STP$
$7200 \,C$ will liberate $ = \frac{22.4}{2\times 96500} \times 7200\,C$
$ = 0.836\,L$