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  4. The volume of CO2 (in cm3) liberated at S.T.P. when 1.06 g of anhydrous sodium carbonate is treated with excess of dilute HCl is [atomic mass of Na= 23]

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Q. The volume of $CO_2$ (in $cm^3$) liberated at S.T.P. when $1.06 \,g$ of anhydrous sodium carbonate is treated with excess of dilute $HCl$ is [atomic mass of $Na= 23$]

COMEDKCOMEDK 2012Some Basic Concepts of Chemistry

Solution:

$Na _2 CO _3+2 HCl \longrightarrow 2 NaCl + CO _2+ H _2 O$
$106 \,g \,22400\, cm ^3$
$1.06 \,g \frac{22400}{106} \times 1.06\, cm ^2$
$=224 \,cm ^3$