1. Tardigrade
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  3. Chemistry
  4. The volume of 2.8 g of carbon monoxide at 27°C and 0.821 atm pressure is(R = 0.0821 lit. atm. mol-1 K-1)

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Q. The volume of 2.8 g of carbon monoxide at 27$^\circ$C and 0.821 atm pressure is$(R = 0.0821 lit. atm. mol^{-1} K^{-1})$

States of Matter

Solution:

Given m = 2.8 g, T = 27$^\circ$, C = 300K and P = 0.821 atm
n = $\frac{m}{M} = \frac{2.8}{28} = 0.1$
According to gas equation
PV = nRT or
V = $\frac{0.0821 \times 300}{0.1 \times 0.821} $ = 3 L