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Chemistry
The volume of 0.1 M oxalic acid that can be completely oxidized by 20 ml of 0.025 M KMnO4 solution is
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Q. The volume of $0.1\, M$ oxalic acid that can be completely oxidized by $20\, ml$ of $0.025 \, M \, KMnO_4$ solution is
KCET
KCET 2012
Some Basic Concepts of Chemistry
A
$125\, ml$
12%
B
$25 \,ml$
20%
C
$12.5\, ml$
57%
D
$37.5\, ml$
12%
Solution:
$N=\frac{\text { molecular weight }}{\text { equivalent weight }} \times M$
$N_{ KMnO _{4}}=\frac{158}{31.6} \times 0.025$
$=0.125$
$N_{ O.A. }=\frac{126}{63} \times 0.1=0.2$
$\because\,\,\, N_{1} V_{1}=N_{2} V_{2}$
$ \therefore \,\,\, 0.2 \times V =0.125 \times 20 $
$V =\frac{0.125 \times 20}{0.2}$
$=12.5 \,mL $