Question

The volume occupied by one mole of water is [ density of water $=1\, gm / cm ^{3}:$

• A. $22400\, cm ^{3}$
• B. $6.02 \times 10^{-23} cm ^{3}$
• C. $3.0 \times 10^{-23} cm ^{3}$
• D. $11200\, cm ^{3}$

Answer 1

Answer: (C)

We know that volume occupied by one
molecule of water $=\frac{\text { mass of water }}{\text { density of water}}$
mass of water $=\frac{\text { molecular weight }}{6.02 \times 10^{23}}$
$=\frac{18}{6.02 \times 10^{23}}$
$=3.0 \times 10^{-23}$
$\therefore $ volume $=\frac{3.0 \times 10^{-23}}{1}$
$=3.0 \times 10^{-23} cm ^{-3}$