Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. The volume occupied by $9.0\, g$ of nitrogen gas at $300 \,K$ and $750 \,mm \,Hg$ pressure is:

AFMCAFMC 2001

Solution:

$P V=\frac{w}{M} R T$
Let $V$ be the volume occupied
$P=750 \,mm =\frac{750}{760} $ atm
$V=? $
$w=9 \,g, T=300 \,K $
$V=\frac{w R T}{M P}$
$=\frac{9 \times 0.082 \times 300 \times 760}{28 \times 750}$
$=8.0125\, L$