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Q.
The volume occupied by $ 16\,g $ of oxygen gas at $ STP $ is
AMUAMU 2013Some Basic Concepts of Chemistry
Solution:
$1$ mole of a gas occupy $= 22.4\, L$ volume at $STP$ therefore, $16 \,g \,O_2$ gas $= 0.5$ mole of $O_2$ gas will occupy $= \frac{0.5\times 22.4}{1} = 11.2 \,L$ at $STP$.