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Q. The volume occupied by 1.8 g of water vapour at 374 °C and 1 bar pressure will be :-
[Use R = 0.083 bar L $K^{-1}mol^{-1}$]

NEETNEET 2019States of Matter

Solution:

$PV = nRT$
$n = 1.8/18 = 0.1 $mole
$P = 1$ bar
$T = 374 + 273$
$= 647 \,K$
$V = \frac{nRT}{P}$
$ = \frac{0.1 \times 0.083 \times 647}{1}$
$ = 5.37\,L$